An exit poll of 1000 randomly selected voters found that 515 favored measure A. a. Construct a 99% confidence interval for the support of measure A. b. Suppose measure A needs at least 50% support to pass, what are the null and alternative hypotheses if we were to test to see if measure A will pass? c. Compute the p-value of the above test.

Answer:Step-by-step explanation:Given that an  exit poll of 1000 randomly selected voters found that 515 favored measure A. Sample proportion p = [tex]\frac{515}{1000} =0.515[/tex][tex]q=1-0.515 =0.485\\n =1000\\SE = \sqrt{\frac{pq}{n} } \\=0.158\\[/tex]Margin of error 99% = 2.58*SE=[tex]2.58*0.0158\\=0.0408[/tex]99% confidence interval =[tex](0.515-0.0408, 0.515+0.0408)\\= (0.474, 0.556)[/tex]------------------------[tex]H_0: p =0.5\\H_a: p >0.5\\[/tex](Right tailed test)STd error = [tex]\sqrt{\frac{0.5*0.5}{1000} } \\=0.0158[/tex]Test statistic Z = p diff/std error =[tex]\frac{0.015}{0.0158} \\\\=0.9487[/tex]p value = 0.1714