I need help breaking this down

Answer:see explanationStep-by-step explanation:Given2cosΘ - [tex]\sqrt{2}[/tex] = 0 ( add [tex]\sqrt{2}[/tex] to both sides )2cosΘ = [tex]\sqrt{2}[/tex] ( divide both sides by 2 )cosΘ = [tex]\frac{\sqrt{2} }{2}[/tex]Since cosΘ > 0 then Θ is in first and fourth quadrants, henceΘ = [tex]cos^{-1}[/tex] ( [tex]\frac{\sqrt{2} }{2}[/tex] ) = [tex]\frac{\pi }{4}[/tex]ORΘ = 2π - [tex]\frac{\pi }{4}[/tex] = [tex]\frac{7\pi }{4}[/tex]solutions are Θ = [tex]\frac{\pi }{4}[/tex], [tex]\frac{7\pi }{4}[/tex]