Q:

Write the slope-intercept form of the equation of each line given the slope and y-intercept.a. Slope= 5, y-intercept= -3b. Slope= -1, y-intercept= 52. Write the point-slope form of the equation of the line through the given point with the given slope.a. Point= (5,3), slope= 4/5b. Point= (-3,-2), slope= -2/33. Write the slope-intercept form of the equation of the line described.a. Point= (1,-1), parallel to y=-6x+1b. Point= (4,5), parallel to y=1/2x+34. Write the standard from of the equation of the line through the given point with the given slope.a. Point=(-4,4), Slope= -7/4b. Point=(1,2), Slope= 6

Accepted Solution

A:
Answer:4b. βˆ’6x + y = βˆ’44a. 7x + 4y = βˆ’123b. y = Β½x + 33a. y = βˆ’6x + 52b. y + 2 = βˆ’β…”(x + 3)2a. y - 3 = β…˜(x - 5)1b. y = -x + 51a. y = 5x - 3Step-by-step explanation:4.Plug the coordinates into the Slope-Intercept Formula first, then convert to Standard Form [Ax + By = C]:b.2 = 6[1] + b 6βˆ’4 = by = 6x - 4-6x - 6x_________βˆ’6x + y = βˆ’4 >> Standard Equationa.4 = βˆ’7⁄4[-4] + b 7βˆ’3 = by = βˆ’7⁄4x - 3+7⁄4x +7⁄4x____________7⁄4x + y = βˆ’3 [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]4[7⁄4x + y = βˆ’3]7x + 4y = βˆ’12 >> Standard Equation__________________________________________________________3.Plug both coordinates into the Slope-Intercept Formula:b.5 = Β½[4] + b 23 = by = Β½x + 3 >> EXACT SAME EQUATIONa.βˆ’1 = βˆ’6[1] + b βˆ’65 = by = βˆ’6x + 5* Parallel lines have SIMILAR RATE OF CHANGES [SLOPES].__________________________________________________________2.b. y + 2 = βˆ’β…”(x + 3)a. y - 3 = β…˜(x - 5)According to the Point-Slope Formula, y - y₁ = m(x - x₁), all the negative symbols give the OPPOSITE TERMS OF WHAT THEY REALLY ARE, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.__________________________________________________________1.b. y = -x + 5a. y = 5x - 3Just write out the Slope-Intercept Formula as it is given to you.I am joyous to assist you anytime.