What is a correct equation for the line passing through the point (-2,1) and having slope m=1/2

Accepted Solution

Step-by-step explanation:The point-slope form of an equation of a line:[tex]y-y_1=m(x-x_1)[/tex]m - slopeWe ahve the slope m = 1/2 and the point (-2, 1). Substitute:[tex]y-1=\dfrac{1}{2}(x-(-2))[/tex][tex]y-1=\dfrac{1}{2}(x+2)[/tex] - point-slope formCovert to the slope-intercept form (y = mx + b):[tex]y-1=\dfrac{1}{2}(x+2)[/tex]          use the distributive property[tex]y-1=\dfrac{1}{2}x+1[/tex]          add 1 to both sides[tex]y=\dfrac{1}{2}x+2[/tex]   - slope-intercept formConvert to the standard form (Ax + By = C):[tex]y=\dfrac{1}{2}x+2[/tex]     multiply both sides by 2[tex]2y=x+4[/tex]        subtract x from both sides[tex]-x+2y=4[/tex]         change the signs[tex]x-2y=-4[/tex]   -  standard formConvert to the general form (Ax+By+C=0):[tex]x-2y=-4[/tex]        add 4 to both sides[tex]x-2y+4=0[/tex]   - general form